The choices are listed in the screen shot below the questions. Only answer is needed, solving steps are not required. Thank you!
Homework Answers
(first part)
(second part)
F=s12/s22=155/99=1.5657
(third part)
p-value=0.2149
(fourth part)
Do not reject null hypothesis, and conclude that there is not enough .........
As the p-value=0.2149 is more than level of significance alpha=0.05(5%)
(fifth part) LCL=0.5026 and UCL=4.877
100(1-
) percent confidence interval
for 
/
is
LCL=1.5657/3.115=0.5026
UCL==1.5657/0.311=4.877
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