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Two blocks are connected by a lightweight, stretchless string and arranged such that the string passes over a frictionless, l
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Answer #1

(A) writing the force equation we have

2.5g - T = 2.5a -----(1)

T = 1.5a -----(2)

adding both equations we have

a = 2.5g / 4 = 2.5*9.8 / 4

= 6.125 m/s^2

(B) Tension = 1.5a = 1.5*6.125 = 9.1875 N

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