Answer)
Null hypothesis Ho : u = 30000
Alternate hypothesis Ha : u not equal to 30000
As the population standard deviation is unknown here we will use t distribution to conduct the test
Test statistics t = (sample mean - claimed mean)/(s.d/√n)
t = (28179 - 30000)/(4546/√7) = -1.06
Degrees of freedom is = n-1 = 6
For 6 dof and -1.06 test statistics
P-value from t distribution is = 0.3299
3)
As the obtained p-value is greater than the given significance 0.05
We fail to reject the null hypothesis Ho
There is not enough evidence to conclude that mean tution fee differs from 30000
Question 2 (1 point) The mean annual tuition and fees for a sample of 7 private...
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