Question

3. (35 pts) A series RLC circuit c circuit is connected to a 5.0 kHz oscillator with a peak voltage of 5.0 V. A) What are the peak voltages on the resistor ontains a SS Ω resistor, a 33 mll inductor, and a 480 F capacitor The inductor, and capacitor? B) When vi.+Vi draw the phasor diagram of the circuit and value of the emf. C) Is it possible for the current in the capacitor and determine the ge on the capacitor to be at the peak values at the same time? Explain.

Answer 1

Given that R = 55 ohm I = 3.3 mH v = 5.0 the relation between the instantaneous emt and i is i = epsilon/R epsilon = iR = IR I = vR implies epsilon = v/R R = 5 times 55/55 = 5 v B)i = epsilon/R epsilon = i R = 3.3 mH times 55 ohm = epsilon = 181.5 c) I = -v/R implies epsilon = -v/R R = -5 times 55/55 = -5