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EXERCISE 1.28. Show that for every positive integer k, there exist k consecutive composite integers. Thus, there are arbitrar

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1.28. Consider (K+1)! +2, (k +1)!+3,[k +)5th,. .,(k+1)! +k+12 These are k consequtive Composite numbers (k+1)!+ in divisible

1.12 to Integers are relatively prime there is no prone that divides both of them. let min e Z. H ged (m,n) adal 4 plm and up

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