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Ideal gas law problem
Ideal gas law problem H_2 Molarity = 0.025 M Volu
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Answer #1

We have the   ideal gas law, PV = nRT.

Where 'P' is the pressure in atmospheres, 'V' is the volume in liters, 'n' is the number of particles in moles,

'T' is the temperature in Kelvin and 'R' is the ideal gas constant (0.0821 liter atmospheres per moles Kelvin).

We have PV =nRT

There fore

P = nRT/V

Here

Molarity = 0.025 M

Volume = 2.00 L

so

n= Molarity x Volume = 0.025 M x 2 L = 0.05 moles

Temperature = 341 K

R= 0.08206

Therefore

P = nRT/V = [0.05 mol x 0.08206 l.atm/k.mol x 341 k] /2 L = 1.399 atm/2 = 0.699 atm

So the answer

P = 0.699 atm

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