A 3.00 cm tall object is 44.0 cm in front of a convex mirror of focal length -30.0 cm. Locate and describe the image
y = 3cm
u = 44 cm
f = -30 cm
1/u+1/v = 1/f
1/v = 1/f-1/u
v = fu/u-f
v = -17.8 cm
magnification m = -v/u = 0.405
y'/y = m
y' = 1.22 cm
image is virtual and upright
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