A 4.50 cm tall object is placed in front a convex mirror with a focal length of -6.25 cm. If the magnification is 1/4, what is the distance from the object to the mirror. Give your answer in centimeter (cm) and with 3 significant figures.
Here ,
height of object , ho = 4.50 cm
f = -6.25 m
magnification , m = 1/4
as m = -di/do
1/4 = - di/do
do = -4 * di ----(1)
Using lens formula
1/f = 1/di + 1/do
-1/6.25 = 1/di + 1/do ---(2)
solving 1 and 2
di = -4.7 cm
do = 18.75 cm
the object is placed at 18.75 cm from the lens
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