Question

Description

An array in C++ is a collection of items stored at contiguous memory locations and elements can be accessed randomly using indices of an array. They are used to store similar type of elements as in the data type must be the same for all elements. One advantage of arrays is easy data manipulation and accessibility of elements stored in consecutive locations.

The Problem:

One teaching assistant of a computer science department in Engineering University got a simple question to solve within time but he is little busy in his new job, so he asked you to solve this problem. He has an array of positive integers A1,A2,...,An with length N and he wants you to print an array of the same length (N) where the values in the new array are the sum of every number in the array, except the number at that index.

Input Format:

First line of input contains N which is the length of the array and second line contains the elements of the array separated by a space.

Enter size of Array:

6

Enter elements of array separated by space:

3 9 2 5 17 25

Output Format:

The program should display a transformed array where each element of the array is the sum of all other elements except the one on that index.

Transformed array:

58 52 59 56 44 36

Answer 1

explnation:

here is first we are reading values into the array then finding the sum of all elements in array then in the new array we are storing the values excluding index value from the sum.

code:

#include <iostream>
using namespace std;
int main()
{
int N,sum=0; //declaring varibles
cout<<"Enter size of Array \n";
cin>>N; //reading the size of array
int a[N]; //declaring array with specifed size
int b[N]; //declaring new array for holding the Transformed array values
cout<<"enter array elements:\n";
for(int i=0;i<N;i++)
cin>>a[i]; //this is for loop to read values
for(int i=0;i<N;i++)
sum=sum+a[i]; //to find the sum of all elements in array
for(int i=0;i<N;i++)
b[i]=sum-a[i]; //storing array values excluding index value
cout<<"Transformed array:\n";
for(int i=0;i<N;i++)
cout<<b[i]<<" "; //displaying output
return 0;
}

OUTPUT

Enter size of Array
6
enter array elements:
3 9 2 5 17 25
Transformed array:
58 52 59 56 44 36

screenshot:

1 #include <iostream> 2 using namespace std; 3 int main() int N, sum=0; //declaring varibles cout<<"Enter size of Array \n"; cin>>N; //reading the size of array int a[N]; //declaring array with specifed size int b[N]; //declaring new array for holding the Transformed array values cout<<"enter array elements: \n"; for(int i=0;i<n;i++) cin>>a[i]; //this is for Loop to read values for(int i=0;i<n;i++) sum=sum+a[i]; //to find the sum of all elements in array for(int i=0;i<N;i++) b[i]=sum-a[i]; //storing array values excluding index value cout<<"Transformed array: \n"; for(int i=0;i<n;i++) cout<<b[i]<<" "; //displaying output return 0; 20 21 } input Enter size of Array enter array elements: 3 9 2 5 17 25 Transformed array: 58 52 59 56 44 36 ... Program finished with exit code o