Question

Sorry there's two questions in the same problem set, if you explain the answer as well as the math thank you!

1a) Tyrone has a glasses with a power of -3 D. (remember : D = 1/m) a) What is their focal length? Are they converging or diverging? b) Is he near- or far-sighted?
c) Is he hyperopic or myopic?

d) What can you say about his NP or FP? e) What do his glasses do?

1b) Jennifer has glasses with a power of +3D

a) What is their focal length? Are they converging or diverging? b) Is he near- or far-sighted?
c) Is he hyperopic or myopic?

d) What can you say about his NP or FP? e) What do his glasses do?

Answer 1

la) a Power, p=-3D a) focal length, fia 12 ta = 3 = -0.33 m Cans) = diverging lens . b) He this year sighted because he needs a diverging (concave) lens. e) He is myopic (which means hear sighted). el) since he is bear sighted, be can clearly neur objects but cannot see fel objects So NP=255.cm (bormal FPZ e) The light rays from feu objects are parallel. 3o it forms image in front ofe retina. A diverging lens diverges the parallel it can form distinct images at retina see . rays so that CS Scanned with CamScanner

16) P =+3D P 1 . a) focal length, f = = +0:33 m =) converging b) He is face-sighted because he is using converging Cconvex) lens He is hypermetropie (which means far - sighted) aus d) He can cleally see fal objects but cannot near objects eleccely see NP >25cm FP = converges e) The rays from a near object are diverging says. so they form image behind retina A convex lens as the the rays and forms a sharp image at retina so that be can see near objects clearly. CS Scanned with CamScanner