Question

14 please help critical t values needed but looks blurry in the pic

This Question: 6 pts 14 of 19 (7 complete) This Test: 100 pts pos A random sample of the birth weights of 186 babies has a mean of 3103 g and a standard deviation of 652 g. Construct a 95% confidence interval estimate of the mean birth weight for all such babies 邑Click the icon to view a table of critical t-values. What is the confidence interval estimate of the mean birth weight for all such babies? 9 (Round to one decimal place as needed)

Answer 1

df = n-1 = 186 - 1 = 185

t critical value at 0.05 significance level and for 185 df = 1.973

95% confidence interval is

df = n-1 = 186 - 1 = 185 t critical value at 0.05 significance level and for 185 df = 1.973 95% confidence interval is x ^bar -t * S/ squareroot (n) < mu < x^bar +t * S/ squareroot (n) 3103 - 1.973 * 652/sqrt(186) < mu < < 3103 + 1.973 * 652/sqrt(186) 3008.7 < mu < 3197.3 3008.7g < mu < 3197.3g
- t * S / sqrt(n) < $\mu$ <
df = n-1 = 186 - 1 = 185 t critical value at 0.05 significance level and for 185 df = 1.973 95% confidence interval is x ^bar -t * S/ squareroot (n) < mu < x^bar +t * S/ squareroot (n) 3103 - 1.973 * 652/sqrt(186) < mu < < 3103 + 1.973 * 652/sqrt(186) 3008.7 < mu < 3197.3 3008.7g < mu < 3197.3g
+ t * S / sqrt(n)

3103 - 1.973 * 652 / sqrt(186) < $\mu$ < 3103 + 1.973 * 652 / sqrt(186)

3008.7 < $\mu$ < 3197.3

3008.7 g < $\mu$ < 3197.3 g