Question

The width of a stacking fault between two Shockley partial dislocations in pure gold was found to be 1.92 nm. The shear modulus of gold is 27 GPa. Calculate the approximate stacking fault energy of gold in mJ/m² (no decimal places).

The width of a stacking fault between two Shockley partial dislocations in pure gold was found to be 1.92 nm. The shear modulus of gold is 27 GPa. Calculate the approximate stacking fault energy of gold in mJ/m2 (no decimal places).

Answer 1

w = width of fault = 1.92 nm. 202 of stacking, stacking 27 apa lingploo FR2.1 1 nm = 10 m odloo 2LOS er $0 1.92 nm = 1.92x 10-m. FI-27323 - w = 1.92x 10-9 m. M = Shear Modulus of gold (GPa) *270 = M = 27 Gla 1 GPa = 109 Pa 80 27 Pa = 27x10 9 Pa. E = 4 Stacking fault Energy ( 51 m2). in the relationshipto 2 tegno deo - 19. I E = co& M .. => E192x10-9 * 27 * 103 >> E = 51.84 Jl m2 1J = 1000 m J 80 1 J/m² = 1000 mJln².. =) 51.84 I = 51.84x 1000 m] m2 - E - S 84 • lo . - E - 51840 mm = 518 40 ml m2 Answer wer