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At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl20(g) + F2。dH'm...
At 25°C, the following heats of reaction are known: AH (kJ/mol 167.4 2CIF + 02 →Cl20...
At 25°C, the following heats of reaction are known: AH (kJ/mol 167.4 2CIF + 02 →Cl20 + F20 2ClF3 + 202 →Cl20+3F20 341.4 2F2 + 02 → 2F20 At the same temperature, calculate ΔH for the reaction: ClF + F2 → CIF3 -43.4 A. -217.5 kJ/mol B.-130.2 kJ/mol C. +217.5 kJ/mol ○ D.-108.7 kJ/mol E. none of these QUESTION 4 Consider the reaction: When a 12.9-g sample of ethyl alcohol(molar mass 46.07 g/mol) is burned, how much energy is released...
At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl2O(g) + F2O(g)...
At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl2O(g) + F2O(g) AHºrn = 167.4 kJ/mol 2C1F3(g) + 202(g) + Cl2O(g) + 3F2O(g) AHºrn = 341.4 kJ/mol 2F2(g) + O2(g) → 2F20(g) AHºrxn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F219) -> CIF3(g) Write answer to three significant figures. NO SIGN in ANSWER. Numeric Response
pter 4-6 0 Saved Help Save At 25°C, the following heats of reaction are known: 2C1F(g)...
pter 4-6 0 Saved Help Save At 25°C, the following heats of reaction are known: 2C1F(g) + O2(g) → Cl2O(g) +F20(g) 2C1F3(g) + 2O2(g) + Cl2O(g) + 3F2O(g) 2F2(g) + O2(g) → 2F20(g) AHO/= 167.4 kJ/mol AHºrn = 341.4 kJ/mol AHºrn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F2(9) --> CIF3(9) Write answer to three significant figures. NO SIGN in ANSWER....
At 25 degree C, the following heats of reaction are known: 2CIF (g) + O_2 (g)...
At 25 degree C, the following heats of reaction are known: 2CIF (g) + O_2 (g) rightarrow Cl_2O (g)+ F_2O (g) Delta H_rxn^degree = 167.4 kJ/mol 2ClF_3 (g) +2O_2 (g) rightarrow Cl_2O (g) + 3F_2O (g) Delta H_rxn^degree = 341.4 kJ/mol 2F_2 (g) + O_2 (g) rightarrow 2F_2O (g) Delta H_rxn^degree = -43.4 kJ/mol At the same temperature, use Hess' law to calculate Delta H_rxn^degree for the following reaction: ClF (g) + F_2 (g) rightarrow ClF_3 (g)
9. Given the following data: 2C1F(g) + O2(g) → Cl2O(g) + F20(g) 2C1F3(g) + 2O2(g) → Cl2O(g) + 3F20 2F2(g) + O2(g)...
9. Given the following data: 2C1F(g) + O2(g) → Cl2O(g) + F20(g) 2C1F3(g) + 2O2(g) → Cl2O(g) + 3F20 2F2(g) + O2(g) → 2F20(g) AH = 167.4 kJ AH = 341.4 kJ AH = -43.4 kJ Calculate AH for the reaction CIF(g) + F2(g) → CIF3(g) 10. Calculate AHº for the following reaction using the AHⓇ information below. 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) AH NH3(g) is -80 kJ/mol AH° NO(g) is 90 kJ/mol AH®, H2O(g) is -242 kJ/mol
13. 10. Using Hess' law, what is all at 25°C for the following reaction? CIF() +...
13. 10. Using Hess' law, what is all at 25°C for the following reaction? CIF() + F:(8) - CIF(e) 2CIF) +0.(g) C12O(g) + OF:) A +167.41J mol 2CIF:(e) +20=(8) -- CLO(g) +30F:(8) A +341.46 mol 2F:() +O )-20F.) A -43.4 kJ/mol A 217.5 kJ/mol B. -130.2 kJ/mol c. 217.5 kJ/mol D. -108.7 kJ/mol 465.4 kJ/mol E 11. What is all for the following reaction? 2H:02(1)→ 2H30(1) - O:(8) APKH:O()) --285.8 kJ/mol; AH® (H:0 (D) - -187.6 kJ/mol A.-196.4 kJ/mol B....
AH° = ? 3.(5pts) Consider the thermochemical reaction: CIF(g) + F (g) ----> CIF3(g) Use the...
AH° = ? 3.(5pts) Consider the thermochemical reaction: CIF(g) + F (g) ----> CIF3(g) Use the following data to determine the value of the missing quantity in the above equation. 2 CIF(g) + O2(g) -----> CI2O(g) + F2O(g) 2 CIF,(g) + 2 O2(g) ----> CI-O(g) + 3 F2O(g) 2 F2(g) + O2(g) -- -> 2 F.0(g) AH AH AH = 167.4 kJ/mol = 341.4 kJ/mol = -43.4 kJ/mol
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) +...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) +...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
3.(5pts)) Consider the thermochemical reaction: 3 CIF(g) + 3F.(g) ---->3 CIF,(g) AHºrn = ? Use the...
3.(5pts)) Consider the thermochemical reaction: 3 CIF(g) + 3F.(g) ---->3 CIF,(g) AHºrn = ? Use the following data to determine the value of the missing quantity in the above equation. 6 CIF(g) + 3 O2(g) ----->3 ClO(g) + 3 F 0(g) 2 CIF3(g) + 2 02(8) -----> CLO(g) + 3 F.0() 2 F2(g) + O2(g) -------> 2 F.O(g) AH AH° AH - 502.2 kJ/mol 341.4 kJ/mol = -43.4 kJ/mol
At 25°C, the following heats of reaction are known: AH (kJ/mol 167.4 2CIF + 02 →Cl20 + F20 2ClF3 + 202 →Cl20+3F20 341.4 2F2 + 02 → 2F20 At the same temperature, calculate ΔH for the reaction: ClF + F2 → CIF3 -43.4 A. -217.5 kJ/mol B.-130.2 kJ/mol C. +217.5 kJ/mol ○ D.-108.7 kJ/mol E. none of these QUESTION 4 Consider the reaction: When a 12.9-g sample of ethyl alcohol(molar mass 46.07 g/mol) is burned, how much energy is released...
At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl2O(g) + F2O(g) AHºrn = 167.4 kJ/mol 2C1F3(g) + 202(g) + Cl2O(g) + 3F2O(g) AHºrn = 341.4 kJ/mol 2F2(g) + O2(g) → 2F20(g) AHºrxn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F219) -> CIF3(g) Write answer to three significant figures. NO SIGN in ANSWER. Numeric Response
pter 4-6 0 Saved Help Save At 25°C, the following heats of reaction are known: 2C1F(g) + O2(g) → Cl2O(g) +F20(g) 2C1F3(g) + 2O2(g) + Cl2O(g) + 3F2O(g) 2F2(g) + O2(g) → 2F20(g) AHO/= 167.4 kJ/mol AHºrn = 341.4 kJ/mol AHºrn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F2(9) --> CIF3(9) Write answer to three significant figures. NO SIGN in ANSWER....
At 25 degree C, the following heats of reaction are known: 2CIF (g) + O_2 (g) rightarrow Cl_2O (g)+ F_2O (g) Delta H_rxn^degree = 167.4 kJ/mol 2ClF_3 (g) +2O_2 (g) rightarrow Cl_2O (g) + 3F_2O (g) Delta H_rxn^degree = 341.4 kJ/mol 2F_2 (g) + O_2 (g) rightarrow 2F_2O (g) Delta H_rxn^degree = -43.4 kJ/mol At the same temperature, use Hess' law to calculate Delta H_rxn^degree for the following reaction: ClF (g) + F_2 (g) rightarrow ClF_3 (g)
9. Given the following data: 2C1F(g) + O2(g) → Cl2O(g) + F20(g) 2C1F3(g) + 2O2(g) → Cl2O(g) + 3F20 2F2(g) + O2(g) → 2F20(g) AH = 167.4 kJ AH = 341.4 kJ AH = -43.4 kJ Calculate AH for the reaction CIF(g) + F2(g) → CIF3(g) 10. Calculate AHº for the following reaction using the AHⓇ information below. 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) AH NH3(g) is -80 kJ/mol AH° NO(g) is 90 kJ/mol AH®, H2O(g) is -242 kJ/mol
13. 10. Using Hess' law, what is all at 25°C for the following reaction? CIF() + F:(8) - CIF(e) 2CIF) +0.(g) C12O(g) + OF:) A +167.41J mol 2CIF:(e) +20=(8) -- CLO(g) +30F:(8) A +341.46 mol 2F:() +O )-20F.) A -43.4 kJ/mol A 217.5 kJ/mol B. -130.2 kJ/mol c. 217.5 kJ/mol D. -108.7 kJ/mol 465.4 kJ/mol E 11. What is all for the following reaction? 2H:02(1)→ 2H30(1) - O:(8) APKH:O()) --285.8 kJ/mol; AH® (H:0 (D) - -187.6 kJ/mol A.-196.4 kJ/mol B....
AH° = ? 3.(5pts) Consider the thermochemical reaction: CIF(g) + F (g) ----> CIF3(g) Use the following data to determine the value of the missing quantity in the above equation. 2 CIF(g) + O2(g) -----> CI2O(g) + F2O(g) 2 CIF,(g) + 2 O2(g) ----> CI-O(g) + 3 F2O(g) 2 F2(g) + O2(g) -- -> 2 F.0(g) AH AH AH = 167.4 kJ/mol = 341.4 kJ/mol = -43.4 kJ/mol
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C He(g) + 6 F2 (g) → 2 CF4(g) + 4 HF (9) can be written as the sum of: CH4 (9) ► 2 C(s) + 2 Ha(o) AH = -52.3 kJ/mol 2 C(s) + 4 Faq) → 2 CF4g) SH -1380 kJ/mol 2 Haq) + 2 Fala) > 4 HF HE.1074 kJimol CsHe(g) + 6 F2 (g) → 2 CF.(g) + 4 HF (g) AH =...
Practice with Hess's Law and Standard Heats of Formation 1. (Example) The reaction C2H4 (g) + 6 F2 (g) → 2 CF4(g) + 4 HF (g) can be written as the sum of: C2H4 (9) ► 2 C(s) + 2 H2 (g) AH = -52.3 kJ/mol 2 C(s) + 4 F2 (9) ► 2 CF4(9) AH = -1360 kJ/mol 2 H2(g) + 2 F2 (g) → 4 HF (a) AH = -1074 kJ/mol C2H4(g) + 6 F2(g) → 2 CF4(g)...
3.(5pts)) Consider the thermochemical reaction: 3 CIF(g) + 3F.(g) ---->3 CIF,(g) AHºrn = ? Use the following data to determine the value of the missing quantity in the above equation. 6 CIF(g) + 3 O2(g) ----->3 ClO(g) + 3 F 0(g) 2 CIF3(g) + 2 02(8) -----> CLO(g) + 3 F.0() 2 F2(g) + O2(g) -------> 2 F.O(g) AH AH° AH - 502.2 kJ/mol 341.4 kJ/mol = -43.4 kJ/mol
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