Q3
Apply Hes Law
if we need ClF + F2 = ClF3
from the data, invert RXN2 since we need ClF3, divide by 2
divide RXN1 by 2, since we need ClF with 1 coeff.
divide RXN 3 by 2, since we need F2 with 1 stoichiometric coeff
HTotal = -341.4/2 + 1/2*167.4 +1/2*-43.4
Htotal = -108.7 kJ/mol
Q4
mol of alcohol = mass/MW = 12.9/46.07 = 0.280
1 mol o = 1.37*10^3
0.280 mol --> X
x = 0.280*1.37*10^3 = 383.6 kJ = 3.84*10^2 kJ
Q5
Q = +20 kJ --> heat release
W = 15 kJ --> work on system
Q-W = dE
a)
is false, Heat flow TO the system
b)
this is true, system is being expanded
c)
False,
Q-W = dE
20-15 = dE = 5
d and e)
false
choose B
At 25°C, the following heats of reaction are known: AH (kJ/mol 167.4 2CIF + 02 →Cl20...
At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl20(g) + F2。dH'm = 167.4 kJ/mol 2ClF3(g) + 202(g) → Cl20(g) + 3F20(g) ΔH'm-34 1.4 kJ/mol 2F2(g) + O2(g) → 2F20(g) ΔHoxn--43.4 kJ/mol At the same temperature, use Hess's law to calculate ΔHorn for the reaction: CIF(g) + F2(g) → ClF3(g) 0 a-21 7.5 kJ/mol O b 465.4 kJ/mol O c. -108.7 kJ/mol d 217.5 kJ/mol O e-130.2 kJ/mol
At 25°C, the following heats of reaction are known: 2CIF(g) + O2(g) → Cl2O(g) + F2O(g) AHºrn = 167.4 kJ/mol 2C1F3(g) + 202(g) + Cl2O(g) + 3F2O(g) AHºrn = 341.4 kJ/mol 2F2(g) + O2(g) → 2F20(g) AHºrxn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F219) -> CIF3(g) Write answer to three significant figures. NO SIGN in ANSWER. Numeric Response
pter 4-6 0 Saved Help Save At 25°C, the following heats of reaction are known: 2C1F(g) + O2(g) → Cl2O(g) +F20(g) 2C1F3(g) + 2O2(g) + Cl2O(g) + 3F2O(g) 2F2(g) + O2(g) → 2F20(g) AHO/= 167.4 kJ/mol AHºrn = 341.4 kJ/mol AHºrn=-43.4 kJ/mol At the same temperature, use the above data to calculate the heat released (kJ) when 3.40 moles of CIF(g) reacts with excess F2. CIF(g) + F2(9) --> CIF3(9) Write answer to three significant figures. NO SIGN in ANSWER....
At 25 degree C, the following heats of reaction are known: 2CIF (g) + O_2 (g) rightarrow Cl_2O (g)+ F_2O (g) Delta H_rxn^degree = 167.4 kJ/mol 2ClF_3 (g) +2O_2 (g) rightarrow Cl_2O (g) + 3F_2O (g) Delta H_rxn^degree = 341.4 kJ/mol 2F_2 (g) + O_2 (g) rightarrow 2F_2O (g) Delta H_rxn^degree = -43.4 kJ/mol At the same temperature, use Hess' law to calculate Delta H_rxn^degree for the following reaction: ClF (g) + F_2 (g) rightarrow ClF_3 (g)
9. Given the following data: 2C1F(g) + O2(g) → Cl2O(g) + F20(g) 2C1F3(g) + 2O2(g) → Cl2O(g) + 3F20 2F2(g) + O2(g) → 2F20(g) AH = 167.4 kJ AH = 341.4 kJ AH = -43.4 kJ Calculate AH for the reaction CIF(g) + F2(g) → CIF3(g) 10. Calculate AHº for the following reaction using the AHⓇ information below. 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g) AH NH3(g) is -80 kJ/mol AH° NO(g) is 90 kJ/mol AH®, H2O(g) is -242 kJ/mol
13. 10. Using Hess' law, what is all at 25°C for the following reaction? CIF() + F:(8) - CIF(e) 2CIF) +0.(g) C12O(g) + OF:) A +167.41J mol 2CIF:(e) +20=(8) -- CLO(g) +30F:(8) A +341.46 mol 2F:() +O )-20F.) A -43.4 kJ/mol A 217.5 kJ/mol B. -130.2 kJ/mol c. 217.5 kJ/mol D. -108.7 kJ/mol 465.4 kJ/mol E 11. What is all for the following reaction? 2H:02(1)→ 2H30(1) - O:(8) APKH:O()) --285.8 kJ/mol; AH® (H:0 (D) - -187.6 kJ/mol A.-196.4 kJ/mol B....
For a reaction of the form A+B → C, the heat of reaction is AH=-56.00 kJ/mol. Which of the following must be true? Mark all that app According to Hammond's postulate the transition state more closely resembles the reactants than the products. The change in entropy for the reaction is positive. The reaction will occur more quickly if the temperature is reduced. None of these must be true.
Calculate ΔG° (in kJ/mol) for the following reaction at l atm and 25°C C2Ho (g)+02 (g)-CO2 (g+H20 () (unbalanced) dG°C2H6 (g) =-32.89 kJ/mol; dG。CO2 (g) =-394.4 kJ/mol; AG。H-O (1) =-237.13 kJ/mol