Question

While L.bc = 2.2 m, L,cd= 1.1 m, D1= 66 mm, Tb= 130 Nxm, Tc = 82.4 Nxm, w= 1250 rpm

4. Figure 5 shows a mechanical power transmission using geared system Electric motor A delivering power to appliance at though gears at B, C, D and E. The dimension notations are given in Table 2 and the values are in FILE-2. Assume torques of the appliances are in clockwise direction (Use GPa G= 78 GPa, v=0.3). You are required to deduce (determine) the following: (a) Torque in shaft AB. 6) Maximum stress, t, and angle of twist, 8, in shaft AB Maximum stress, t, and angle of twist, 0, in shaft BC d) Maximum stress, t, and angle of twist, 8, in shaft CD (e) Maximum stress, T, and angle of twist, 6. in shaft DE (1) Power supplied by motor A. Table 2 PART/POINT LENGTH(m) DIAMETER (mm) [5 marks) [10 marks] [10 marks] [10 marks] [10 marks) [5 marks] TORQUE (Nm) SPEED (opm 20 0.8 Lbc Lcd 1.4 60 DI DI 50 00 milloluluilalul AB BC CD DE B с D E TO TC 60 50 B D E Figure 5

Answer 1

Table Part (Point length im Diameter (mm) Tongue ino) speed lopm) AB 0.8 60 Lo = 1250 BC 2.2 D1 = 66 mm 1250 loi Di = 66 120 DE 1.4 SO 1250 To = 130 С. Tc=82.4 60 4 50 E Given loca = 2.2m ; Lea-lom Og = = 66 mm ; To = 130 Nm Te=8204 Nm and w=1250 apm G=078 GPa &0=0.3 Pa) Toe = 50 Nm To = To + TE = 50 +60 = 110 Nm Toc = TC + Totte = 110 +82.4 = 192.4 Nm 32 a. 4 Nm TAB = TB + TBC = 192.4 + 130 | TAB = 32204 wml Nero 49 TAB = 32204 Nm 4 Rdt om 32 32 710.0%) JAB = 1.272 eded x 106 322.4 X 0,03 JAB = 7.60 MPa 1.212x156 Emax = 7.60 M897 TOTAB T =

EART TABLAB G JAB OAB -2 2.594S ҳ10 т. = 322.Чxo.g 18x49x),22 x64 Wa-b4%я [eme =o.1489 - Тес = 192.4 Nm (calculated in Post a ) Joe= ade xioo mt т (о, със + 1863 ХIO 3. 32. Свся Тge Tec JBC 192.4х0,033 1,86 2 хос = 2.0 4 x Чес - 246g M04. бgs = с Tec Lge G JBC 142, 4x22 = 2.4ig хотод 78 xi° x 1,362 x64 о Фрс - о. 16634 d Tcp=110 Nm [.: Calentated in Pasta) ada т х(o.azd)* -6 - 1,8 62 x 10 Jcp Р 32 3 = 1,4 48 Yo’ra TED = То ҳҮер Jco То хо,033 (863 x66 Сер - (494& MP4

O co = Teo Leo G Jco 110 x lol 78x109x 0.833x10² rad 'x1.8636106 Scp = 0.0477 TE = 50 Nm 4 adh LA = 6.1359x10 À (0.05) IDE me 32 32 Pa = 0,2037x10? TOE = TOE VDE Joe 50 X 0.025 601359x107 ZDE = 2.03 MPa I = ODE = Toe LDE G JOE o Sox 1.4 78x109 x 6.1359 xio ODE = 0.1462 x 10² rad ODG = 0.08389 - OAB to Be toco + Ope total twist Power supplied = Torque o &(1250) = 130.899 7 mois w= 60 Power TAB Power 322.4 x 130.8997 = 42204. 256 kW