Question

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Q.2. (8 Marks) The 50-mm-diameter shafts AB & DE are made of A-36 steel (G - 75 GPa) and are supported on journal bearings that allow the shafts to rotate freely and the turbine at E is fixed from turning. If the allowable angle of twist of C with respect to E is 0.2° and shaft AB rotates at 30 Hz, determine the maximum power (hp) that can be delivered from the motor Motor 1.5 m DA Somm 0.5m 75 mm 0.75 m Turbine 1

Answer 1

Write the equation for angle of twist at C. TcLCE GJ cs GJECE (75*10*)(55 (75)") 0.2°x 32 180° (0.75x10") TC ICE = 1084307.12 N-mm = 1084.31 N-m Write the equation for torque ratio. T; -d; Tc dc Tg (50) (1084.31) (75) = TE (50)x(1084.31) = 722.87 N-m (75) Calculate the maximum power that can be delivered from the motor. Pro = Tg@=T;(21f)=(722.87)(27(30))=136257.78 W 2182.72 hp