Question

The two shafts are made of A-36 steel. Each has a diameter of 23 mm and they are connected using the gears fixed to their ends. Their other ends are attached to fixed supports at A and B. They are also supported by journal bearings at C and D, which allow free rotation of the shafts along their axes. A torque of 500 N·m is applied to the gear at E as shown in the figure below. The shear modulus of elasticity for A-36 steel is 75 GPa. (Figure 1) Part A Determine the rotation of the gear at E. Express your answer using three significant figures. IVO AED 11 vec ? 0 = 0.0140 rad Submit Previous Answers Request Answer X Incorrect; Try Again; 2 attempts remaining Provide Feedback Figure 1 of 1 50 mm 0.75 m 100 mm 500 N·m 1.5 m

Answer 1

Step to find the internal torque In two shaft > Free 500 Nim TA TA+F8 - 500 = 0 TA + 0.1F - 500 = 0 - 0 Tg = 0.05F from equation and TA + 2 Tg = 500 Now we know 6 0.1 PE = 0.05DF. 2 TEALEA = IB4B JEB GFB JEA bien To(0.75) = 2 TA (115) TA = 0.25 To. 6 and ea 4 Solving = 222.222 N.m. To TA = 55.555 Nm

Qo = TALEA GEA JEA = 55.555 (105) (0.023)* x 75X10° 7 32 0.04044286 sad In three significant figure ! rad DE = 0.0404