(1) mean = 70000
Standard deviation = 9000
Z score for 60000 = 60000 - 70000/9000 = - 10000/9000 = -1.11
Area under z score - 1.11 = 0.1335 ~ 15%
Option (a) 15%
(2) mean = 45000
Standard deviation = 8000
by seeing the z score table we can say that for 95% the z score should be = 1.65
Now, let the salary be x
As we know the z score so
X - 45000/8000 = 1.65
=> x - 45000 = 1.65 × 8000
=> x - 45000 = 13200
=> x = 58000
And we will take it as + 13200
So the range of the salary will be 31800 to 58200
Option (b) is correct 29000 to 61000
(3) mean = 45000
Standard deviation = 8000
Z score for 50000 = 50000 - 45000/8000 = 5000/8000 = 0.625
Area under z score 0.625 = 0.7324
As it is asked more than 50000, so we will subtract it from 1
= 1 - 0.73
= 27
Option (c) is correct about 27%
(4) mean = 45000
Standard deviation = 8000
Z score for 35000 = 35000 - 45000/8000 = - 10000/8000 = -1.25
Area under z score - 1.25 = 0.1056
Z score for 50000 = 50000 - 45000/8000 = 5000/8000 = 0.625
Area under z score 0.625 = 0.7324
So difference between is = 0.7324 - 0.1056 ~ 63%
Option (c) is correct about 65%
Note:- only 4 questions are allowed to answer as per HOMEWORKLIB RULES if a list of questions are asked
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