Question

help on #3 parts b and c pls

3. A 2.5-kg projectile is fired from an 85 m high cliff at an upward angle of 35° with a speed of 47 m/s. Neglecting air resistance, calculate: a. The total mechanical energy (kinetic + potential of the projectile EK+U 20 K, +U, = K2 + U - ² mv ²+mgy, = {(2,5)(47)24 12,5)(9.8)(85) -4843,75-4800J b. The kinetic energy of the projectile when it reaches its highest point kto mechanical er C. The highest height that the projectile reaches

Answer 1

when Parlic to the maximum height then wy o oney is present. N . now, ovo gt =vosina x = No casa n uagt = vosinx tua vosina (as starting relocity i kinetic energy of the particle at it's highest point - ma (no, wy) KE = 12 m Vocosa = // 2 x 2,5 x Cut) & (688 350g = 1852.8 T @ Highest height (H); we have a Nosind - the time take " I to go to highest light. i H = Nosins. Nosind Eg. Prosina to sina (at t=t) 2g dir H = (47) + (sin35 249.8 I 237 m above the Total height = 85 +37 = 122 m (from grounds liss).