Question

Assignment Problems: 1) An insulating rod of length L-8.15 cm is uniformly charged with (the prefix femto is a personal favorite ar lis 10-15) 4.22 fC total. (a) What is the linear charge density of the rod in Cm and electrons are attached to the rod? w many total excess (b) what is the electric field at point P (it's a vector, so bot agnitude and direction!). P is a 12.0 cm away from the end of the rod. The challengere is to work out all the steps from the Coulomb Field law, from scratch, showing logie. Not plug and chug, (C) repeat if "a" was 50 minstead? (d) at 50 m, what if it wasn't a rod but a point charge with the same "q"?

Answer 1

Thank you. I have taken reference to the given diagram please lile the answer. ASAP.

Here given Rod charge length , q = L = ==4.22 8-15 cm fc © - -4.22 xio's linear chao se dens, te, da 43.15 3152 340.5178 x 1543 c/m :13 - 5.135 x Höhe com? – 4.22 x 17'S = 2.634 x 104 electrons na No.of eo -)-602 xio's ka → © At distance 9 - 12 cm Electric field , Esa ka[á - atel svog saja (iz - bert] TE -461023 x 1ő3 Vim © 14 78 x 50+0.0851 E -- of a = som. 17--9x10 tath to Escom = – 1-5818 x 10 V/m. fes Rod be a point charge. ,82.50m E = ka = -6x10°x 4.22X17"S = 15:192 xföºmai o (SO) 2