Homework Answers
As we know that
Electric poteteial
KQ/R = 10^6
(9*10^9)*Q/0.10 = 10^6
Q = 1.11*10^-5 C
Therefore
4piR^2*Density = 1.11*10^-5
Density = 8.8*10^-5 C/m^2
D option
Required Potetenial = kQ/R
= (9*10^9)*(1.11*10^-5)/(0.20)
= 500*10^3 V/m
A option
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