a = v^2/r
a = sqrt(10^2 + 6^2) = sqrt(136)
Distance particle has moved = (angle moved through)*radius =
(pi/2)*r
Distance = velocity*time = v*t
v*t = (pi/2)*r
Using t = 2 we have v = (pi/4)*r
a = [(pi/4)*r]^2
r = a/[pi^2/16] = 16*a/pi^2 = 16*sqrt(136)/pi^2
r = 18.90 meters
Chapter 04, Problem 063 At t, -5.00 s, the acceleration of a particle moving at constant...
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