Question

68 An RLC circuit with a parallel bypass resistor (Problems 3.10 and 5.11) is shown in Fig. P6.8. At time t 0 the circuit has

Simulink and matlab solution needed for this question

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Capacitor initial voltage V= Q/C= 0.01/0.04 = 0.25 Volts

Inductor initial current = 0 Amps

Discrete 5e-05 s 0.4 Ohm powergu Scope Voltage Across the capacitor C 0.2 Ohm L=0.01 H Voltage Measurement C 0.04 F AC Voltag

Voltage Across the capacitor C 0.6 0.4 0.2 -0.2 0.4 -0.6 1.5 0.5 Time (secs)

Add a comment
Know the answer?
Add Answer to:
Simulink and matlab solution needed for this question 68 An RLC circuit with a parallel bypass...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Use MATLAB simulink 6.8 An RLC circuit with a parallel bypass resistor (Problems 3.10 and 5.11)...

    Use MATLAB simulink 6.8 An RLC circuit with a parallel bypass resistor (Problems 3.10 and 5.11) is shown in Fig. P6.8. At time t-0 the circuit has zero current in both loops and the capacitor C has a stored charge of 0.01 C. The system parameters are R1 = 0.4 Ω, R2-0.2 Ω, C = 0.04 F, and L = 0.01 H. Use Simulink to obtain the system response where the source voltage is a sinusoidal function, en()0.5 sin 10t...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT