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Use MATLAB simulink
6.8 An RLC circuit with a parallel bypass resistor (Problems 3.10 and 5.11) is shown in Fig. P6.8. At time t-0 the circuit has zero current in both loops and the capacitor C has a stored charge of 0.01 C. The system parameters are R1 = 0.4 Ω, R2-0.2 Ω, C = 0.04 F, and L = 0.01 H. Use Simulink to obtain the system response where the source voltage is a sinusoidal function, en()0.5 sin 10t V. A voltmeter is used to measure the voltage across the capacitor C. Plot Simulinks prediction of the voltmeter output for a simulation time of 1.5 s R2 ein(t) Figure P6.8
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untitled Simulink Hile Edit Vview Display Diagram simulation Analysis Code Tools Help Normal nttied Br es RLC Bardh Stope Bar0 Hile Toos View Simulation Help 04 05 Ready 0857 O Type here to search @ fa /.10廡划葵ENG 24-04-2018i took RLC sereis branch and i put indutor is zero and capacitor is infinite for resistor,,..similar for another elements

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