İleri besleme kullanılan zorlanmış üç etkili bir evaporatör, 38,1 °C’deki 13658 kg/h debiye sahip %15 NaOH çözeltisi beslenmekte ve evaporasyon işlemi sonunda çözelti %50’ye derişiklendirilmektedir. Isıtma için kullanılan su buharları doygun olarak bilinmektedir ve ilk evaporatöre beslenen buhar basıncı gösterge basıncı olup 56,6 kPa’dır. Üçüncü etki içerisindeki basınç 6,76 kPa’dır. Isı aktarım katsayıları sırasıyla U1=6246, U2=3407 ve U3=2271 W/m².K olarak verilmektedir. Üç etkinin de yüzey alanı eşittir. a) yüzey alanlarını ve b) su buharı tüketimini hesaplayınız.
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A forward feed triple effect evaporator is used to fed 13608 kg/hr of NaOH solution containing 10 wt% solute. The entering feed temperature is 37.8°C. It is to be concentrated to a 50% NaOH solution. The steam used to enter at 58.6 kPa gage. The absolute pressure in the vapor space the third effect is 6.76 kPa. The heat transfer coefficient are U;=6246, U.=3407, and Uz=2271 W/m²K. All effects must have the same area. Calculate the surface area and steam...
You need a rented apartment and you can see that the 3rd floors of each of the 2, 3 and 4 blocks of the buildings built in adjacent order as shown in the figure (front side) are for rent. You also learn that Block 2 is heated by a coal boiler operating at 75% efficiency, Block 3 is heated by a natural gas boiler operating at 92% efficiency, while Block 4 is heated by a heat pump with a COP...
Evaporation of Sugar Solution in a Multiple-Effect Evaporator. A triple-effect evaporator with forward feed is evaporating a sugar solution with negligible boiling- point rise (less than 1.0 K, which will be neglected) and containing 5 wt% solids to 25% solids. Saturated steam at 205 kPa abs is being used. The pressure in the vapor space of the third effect is 13.65 kPa. The feed rate is 22 680 kg/h and the tempera- ture 299.9 K. The liquid heat capacity...
Please answer A, B, and C in full 2. Let f() € F[2] be a separable polynomial with roots {u1, ..., Un} contained in some splitting field K of f(x) over F. Define A= || (ui-u) = (ui - U2) (u - u3) ...(ui-un)(uz - u3) ..(un-1 - Un) EK. (a) (15 points) Consider GalpK < Sn by looking at its action on the set of roots for f(x). Show that if Te Galo K is a transposition then (A)...
Er<E EF E E> E) W>0) and Polytropic PathsSpcl Cases for Ideal Gas n 0 constant pressure n 1 constant temperature n k constant entropy, adiabatic (q 0) n constant volume and W<0 W 0 For air R 0.287 kJ/kg-K and k Cp/Cv 1.4 if pi 300 kPa, v, 0.861 m3/kg then T, 900 K For T Ta if pa /p 3 then va = m2/kg pv RT and (T, n/(n-1) p2 V1 For vi v if po /p1 3...
Otomatik Kaydet a H 01 - Excel e Ara 7 Goncagül Kale GK Х Dosya Giriş Ekle Sayfa Düzeni Formüller Veri Gözden Geçir Görünüm Geliştirici Yardım Paylaş Açıklamalar Ekle Calibri 12 y Α' Α' == ab Metni kaydir Genel WE ÀY DX Sil Yapıştır ΚΙ Αν 60.00 A Birleştir ve Ortala v Duyarlilik C-% od v Koşullu Tablo Olarak Hücre Biçimlendirme Biçimlendir Stilleri Stiller Biçim Sırala ve Filtre Bul ve Uygula Seç Pano Yazı Tipi Hizalama Sayi Hücreler Düzenleme Duyarlılık...
The figure below shows a plot of potential energy U versus position x of a 1.04 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are U1 = 15 J, U2 = 30 J, and U3 = 40 J. The figure below shows a plot of potential energy U versus position x of a 1.04 kg particle that can travel only along an x axis. (Nonconservative forces are...
11. How high should an object go so that its potential energy gain is the same as its kinetic energy when it was moving at 20 m/s? 12. A 2000 kg carriage moves with an initial velocity of 25.0 m/s on horizontal road slides to a stop at a distance of 60.0 M. (a) Find the work done by the kinetic friction force in the carriage. (b) Determine the kinetic friction coefficient between the wheels and the road. Ans: (a)...
The figure below shows a plot of potential energy U versus position x of a 1.36 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) In the graphs, the potential energies are U1 = 15), U2 = 30 ), and U3 = 40 ). Ur--- - U (1) --- + - --- 2 4 6 x (m) The particle is released at x = 4.5 m with an initial speed of 6.0 m/s, headed...
questions 1 & 2 Caleulations: Mo lanly of ThOf is 0.25M Sampfe cfD ,2 adu 15 ml MaCl d a25 NACH KO.OISL 0.00325 mal NaOk kons vinalold md of NaOH nal HC2H,O M HC a00375 HC7Of = O.125 M HGHy9 O.03 L Sanple Ns md Ot 5m MO0.01KL- acou, de HOan atulo MHABOecoM H o 0.133m HC2H2 O.03L Jini goiba tond I Questions Jond laitial 1. The manufacturer of the vinegar used in this experiment claims that the vinegar contains...