Question

Fill in the blanks in the table: Symbol of element A 34 Z 16 Protons 8 76 Neutrons 8 114 Electrons 10 18 Net charge +3 14 13 TA 7 9 10 1 2 1008 A 3 Be 6.94 9.01 11 12 Na 3 ME 22.99 24.30 SI 19 20 21 C Sc 39.10 40.0 44.95 37 38 39 Rb Sr Y 8547 87.62 $8.91 55 56 57 Ba La 132.91 137.33 18891 12.01 14 SI 28.09 32 28 BA 2 15 16 17 He SA TA 4.003 7 8 10 Ne 14.01 16.00 19.00 2018 IS 16 17 18 S a 30.97 32.07 35.45 39.95 33 34 35 36 As Se Br Kr. 74.92 78.96 79.90 83.80 51 52 53 54 Sb TS 121.75 1276 126.90 13129 83 85 86 Bi Po AL RA 208.98 2089 2099902 24 Cr $2.00 26 Fe 5585 72.61 4 5 SB 22 23 TI 47 $0.94 40 41 24 Nь 91.22 92.91 72 73 HI 17849 18095 104 OS RE Db 2611 M21 27 C SR93 45 Rh 102.91 B 10.81 13 11 AI 18 28 26.98 30 31 ZA Ga 63.54 65.39 69.72 47 48 Ag In 10787 112.41 11482 79 81 Au Hg TI 196,97 200.9920435 111 112 Re Co 272 25 25 Ma 54.94 43 TC 98.91 75 RE 1862 107 58.69 46 Pd 106.42 3 Mo 95.94 74 w IRIS 106 Sg 261 Se 11871 Re 101.07 76 Os 1902 108 Hs 2651 Pb 2012 Ir 192.22 109 Mt 2661 PE 195 OR 110 Ds 271 Ra Ac 221.02 22603 227.03 Lanthanides 58 59 60 61 64 65 66 67 Pr Nd Pm 140.1214091 Gd Tb Dy 4424 Ho 1506 151.97 157.25 158.93 162.50 164.93 167.26 90 91 93 94 96 98 Th 100 Pa U Np Pu Am Cm C ES 232.04 231.04 238.03 237.05 244.06 243.06 24707 247.07 251.08 252.08 257.10 20 Tm Yb 173.04 17497 101 100 103 No 1. 258.10 252.10 260.11 Actinides

Answer 1

ATOMIC NUMBER(2), The number of Protons Present in erre nucleus ot atom of au element is called Atomic Number (2) mass Number (A): The total no of nucleaus ( protons + Neutraus) present in the nucleus at atau of an element is called mass Number (A). mass Number (A) = no caprotaus t no ct Neutrous -) A 1). z + N =) No et neatsaus (N) A-2. for column In no of proteus = 8 =) Afcruic Alau'c no(2)=8 No of Neutrous = 8 mars no (A) 2 2 + N 8+8=16, Electraus 10 Net charge a Electron charget proton Charge

10X(-1) + 8 x(+)). -10 +82-2. Symbol of element o 0²- For Column-In A = = 34 (malo number). Alauic no (2) - 16. no ct proting - Afaucic no = 16, No of Neutrous (N) = A-Z 34-16-18 Electrous 181 Net charge = charge an electraus + charge an Protous 181-1) + 16(+1) 3-2. Symbol of element is: 2- 5? for Column - a no of proteus (2) - 76, no of Neutrass (N) = 114, IRI mass no (A) = 2 + N 76 +114.3 190, Electrons = ? (let it be! x) Net charge = + 3 + 3 = 76(+1) + X(-1) 76-3373, x = No of electrons a 73, symbol of element is: ost3

Tables 2 Symbolct element o² Ost3 34 190 A 16 76 16 z 8 16 protans 76 8 18 114 8 Neutraus 18 73 Electrous 10 2 -2. +3. Net charge