The rate of effusion or diffusion is inversely proportional to the square root of molar mass of the
gases.
Therefore, the ratio is given as follows:
\(\begin{aligned} \frac{r_{C O}}{r_{N H_{3}}} &=\sqrt{\frac{M_{N H_{3}}}{M_{C O}}} \\ &=\sqrt{\frac{17 \mathrm{~g} / \mathrm{mol}}{28 \mathrm{~g} / \mathrm{mol}}} \\ \frac{r_{C O}}{r_{N H_{3}}} &=0.78 \\ r_{M H_{3}} &=1.3 r_{\mathrm{CO}} \end{aligned}\)
Hence, the correct answer is (b). That is, the rate of effusion for \(N H_{3}\) is 1.3 times that of \(C O\) .
If CO and NH3 are allowed to effuse through a porous membrane under identical conditions, the...
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