this problem is based on graham's law of diffusion.
graham's law states that the rate of diffusion or of effusion of a gas is inversely proportional to the square root of its molecular weight.
molar mass of unknown hydrocarbon =1592.04 g/mol
7. A gaseous hydrocarbon is found to effuse through a porous barrier in 1.50 min. Under...
A sample of CH4 gas is observed to effuse through a porous barrier in 6.35 minutes. Under the same conditions, the same number of moles of an unknown gas requires 14.8 minutes to effuse through the same barrier. The molar mass of the unknown gas is ___g/mol.
A sample of He gas is observed to effuse through a porous barrier in 8.83 minutes. Under the same conditions, the same number of moles of an unknown gas requires 30.1 minutes to effuse through the same barrier. The molar mass of the unknown gas is ___ g/mol
1. The rate of effusion of CH4 gas through a porous barrier is observed to be 9.17*10^-4 mol/h. Under the same conditions, the rate of effusion of gas would be _____________ mol/h. 2. A sample of N2 gas is observed to effuse through a pourous barrier in 1.93 minutes. Under the same conditions, the same number of moles of an unknown gas requires 2.97 minutes to effuse through the same barrier. The molar mass of the unknown gas is _______________
a sample of CO2 gas is observed to effuse through a pourous barrier in 4.05 minutes. Under the same conditions, the same number of moles if an unknown gas requires 4.28 minutes to effuse through the same barrier. The molar mass of the unkown gas is what?
A sample of He gas is observed to effuse through a pourous barrier in 8.78 minutes. Under the same conditions, the same number of moles of an unknown gas requires 22.1 minutes to cffuse through the same barrier. The molar mass of the unknown gas is 18 mol Submit Answer Retry Entire Group 3 more group attempts remaining
An unknown gas effuses through a barrier in 3.5 minutes. Under identical conditions it takes an equal amount of argon gas 2.8 minutes to effuse through the barrier. What is the molar mass of the unknown gas?
8. Neon gas is found to effuse through a hole. Careful measurement indicates that 1.42 x 10 mol effused in 5.8 minutes. How long (in min) would it take for the same amount of xenon gas to effuse through the same hole under the same conditions? A: 14.8 RKSHEET 9 9. A 2.00 L bottle contains the following gases: 0.0150 mol He, 0.100 mol Ny, and 0.00250 mol Xe. If the temperature of the gas mixture is 22.4 °C, what...
The rate of effusion of NH3 gas through a porous barrier is observed to be 3.47 x 10 mol/h. Under the same conditions, the rate of effusion of O2 gas would be mol/h.
8. Neon gas is found to effuse through a hole. Careful measurement indicates that 1.42 x 10 mol effused in 5.8 minutes. How long (in min) would it take for the same amount of xenon gas to effuse through the same hole under the same conditions? A: 14.8
A gas of unknown molecular mass was allowed to effuse through a small opening under constant pressure conditions. It required 52 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 27 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; that is, rate and time are inversely proportional.)...