(d)
Required production per year = 30,000 units
Available time per year = 50*5*8*60 minutes = 120,000 minutes
So, the required cycle time = 120,000 / 30,000 = 4 minutes
Station | Remaining time | Eligibles | Was fit | Assigned time | Time remains | Idle time |
I | 4 | A | A | 4 | 0 | |
0 | B | - | - | 0 | 0 | |
II | 4 | B | B | 3 | 1 | |
1 | C, D | - | - | 1 | 1 | |
III | 4 | C, D | C | 4 | 0 | |
0 | D, E, F | - | - | 0 | 0 | |
IV | 4 | D, E, F | E | 4 | 0 | |
0 | D, F | - | - | 0 | 0 | |
V | 4 | D, F | D | 3 | 1 | |
3 | F, G | F | 1 | 0 | ||
0 | G | - | - | 0 | 0 | |
VI | 4 | G | G | 2 | 2 | |
2 | H | - | - | 2 | 2 | |
VII | 4 | H | H | 4 | 0 | |
0 | I | - | - | 0 | 0 | |
VIII | 4 | I | I | 3 | 1 | |
1 | - | - | - | 1 | 1 |
So,
Eight stations as above will be formed with eight workers working on each station.
(e)
Required production per year per line = 15,000 units
Available time per year = 50*5*8*60 minutes = 120,000 minutes
So, the required cycle time = 120,000 / 15,000 = 8 minutes
Station | Remaining time | Eligibles | Was fit | Assigned time | Time remains | Idle time |
I | 8 | A | A | 4 | 4 | |
4 | B | B | 3 | 1 | ||
1 | C, D | - | - | 1 | 1 | |
II | 8 | C, D | C | 4 | 4 | |
4 | D, E, F | E | 4 | 0 | ||
0 | D, F | - | - | 0 | 0 | |
III | 8 | D, F | D | 3 | 5 | |
5 | F, G | G | 2 | 3 | ||
3 | F | F | 1 | 2 | ||
2 | H | - | - | 2 | 2 | |
IV | 8 | H | H | 4 | 4 | |
4 | I | I | 3 | 1 | ||
1 | - | - | - | 1 | 1 |
So,
Both the single lines will contain four stations with one worker working in each station. So, the number of workers required will still be eight.
(f)
Total idle time per cycle in the single line = 0+1+0+0+0+2+0+1 = 4 minutes, Balance delay = 4 / (8*4) = 12.5%
Total idle time per cycle in the double line = 1+0+2+1 = 4 minutes, Balance delay = 4 / (4*8) = 12.5%
So, in both the cases, the resources seem to be equally loaded. Using overtime in each of these two cases should be indifferent.
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