Question

This assignment is set up for sequential assessment. Complete each question and submit the answer before moving on to the next question. Correct answers for each question will be made available once the maximum number of attempts have been made for each submission. Resistance and Resistivity A = area L = length p = resistivity R R =p A (a) A resistor is made of tungsten filament whose resistivity is rou = 5.60x10^-8 sm. Its cross-sectional area is A = 6.40x10^-9 m2. Its length is L = 0.490 m. Calculate its resistance. Keep 3 decimal places. Enter a number 12 Submit (5 attempts remaining) (b) A resistor of 1.863 2 is made of a wire whose length is 0.130 m and whose cross-sectional area is 1.20x10^-9 m2. What is its resistivity? Write the resistivity in terms of 10-8 sm. For example, if the result is 1.23x10-82m., just enter 1.23. Enter a number x10-82m Submit (5 attempts remaining) (c) A resistor of 2.800 is made of tungsten filament whose resistivity is rou = 5.60x10^-8 m. Its cross-sectional area is A = 4.20x10^-9 m2. Calculate its length. Keep 3 decimal places. Enter a number m Submit (5 attempts remaining) (d) A resistor of 3.578 2 is made of tungsten filament whose resistivity is rou = 5.60x10^-8 Sem. Its length is 0.230 m. Calculate its cross-sectional area. Write the area in terms of 109 m2. For example, if the result is 1.23x109 m2., just enter 1.23. Enter a number * 10-9m2 Submit (5 attempts remaining) What is the Diameter of the wire in (d)? Write the diameter in terms of 105m. Keep 2 decimal places. Circular cross-sectional area = ser2, diameter = 2x radius Enter a number X10-9m Submit (5 attempts remaining) (e) If the diameter in (d) is halved while the length is unchanged and the material is unchanged, what will be the new resistance? Enter a number Submit (5 attempts remaining)

Answer 1

a) Given 8 = 5.60x108rm A 6:40x100 m² ta 0.490m Resistance R, IL А 8 5.60810_nm x 0.490m 6:40x109 mi A.28702 4:288_12 b) AR Given R=1:8637 LE 0-130 m A = 1.20x109 m² Resistivity, I = 1.20x10 m.x1.863.9 0.13om 1.71969x108m 8 cl.72x10 nm. L 9 2 c) Cinen R7 2800.1 8 = 280 on 5.60x10 cm 4.20x109 m² A

S = AR L AR P a A.20x 10 m 5.60 x 10 S 2 x 2.800 8 sm 0.210m a) given R=3.5784 % = 5.60 x 108m he 0.230m S AR A SL R = 5.60x10 cm xo:2 30m 3.57812 -9 3.59971x10 m ~ 3.60xl A = 78² = 5 d² 2 2 id= 2 Sala

d=ax 3.6x109 m² ñ 6.77 X10 m - d/2 2 d'. A 1 (0/2) 4 ta? 4x4 4 Area is sidneed to its one fourth A . R = A. R' = 8 l A14 = 4R Resistance will increase to form times R 14.312.0 - HX 3.5781