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Given C2H6 (g) ---> 3H2 DeltaH: 84.7 KJ Give the enthalpy for 4x reverse reaction and...

Given C2H6 (g) ---> 3H2 DeltaH: 84.7 KJ

Give the enthalpy for 4x reverse reaction and for making 556 grams of H2 product. (two part problem)

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Answer #1

A) enthalpy for 4 × reverse reaction

∆H° = -4×84.7 => -338.8 kJ

B) enthalpy for making 6 g H2 = 84.7 kJ

Enthalpy for making 556 g H2 = 84.7×556/6.0

∆H = 7848.9 kJ

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