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what is the actual van't hoff factor for an aqueous 0.20 molal solution of FeCl3 if...

what is the actual van't hoff factor for an aqueous 0.20 molal solution of FeCl3 if the freezing point is -1.2C? assume the Kf of water is 1.86C/m

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Answer #1

ATF = ix KfXm Af= change in freezing point → 1.2 - ix 1.86X 0:2 is to 2 1.864002 La in vant of factor Me molality Kf= 1.86c/o

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