At what temperature would a 1.40 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86 ∘C/m . Express your answer with the appropriate units.
At what temperature would a 1.40 m NaCl solution freeze, given that the van't Hoff factor...
5) At what temperature would a 1.55 m NaCl solution freeze, given that the van't Hoff factor for NaCl is 1.9? Kf for water is 1.86 .C/m. The freezing point for pure water is 0.0 °C and Kf is equal to 1.86 °C/m.
Colligative properties, such as boiling point elevation, depend on the number of dissolved particles in solution. For nonelectrolytes, no dissociation occurs, and so you can use the number of moles of solute to calculate both molality and molarity. In contrast, electrolytes dissociate, and therefore the molality and molarity must be calculated based on the number of moles of dissociated particles or ions. There are two ions per formula unit of NaCl. Therefore, we would expect the freezing-point depression ΔTf of...
Freezing point depression can be used to experimentally determine the van't Hoff factor of a solute in solution. Given the data in the table, please answer the questions below and determine the "real" van't Hoff factor of the solute. Experimental Results Mass of solvent (water) Freezing point of water Freezing point depression constant (Kf) of water Mass of solution Freezing point of solution 8.515 g 0.00°C 1.86°C/m 9.3589 -5.45°C a. What mass of solute was used? b. What is the...
Calculate the osmotic pressure of a 0.0515 M NaCl solution at 25°C. (The van't Hoff factor for NaCl is 1.90)
You have a aqueous solution of NaCl that has a freezing point of -9.35°C. Assuming a van't Hoff factor of 1.9 for NaCl, what is the mass percent of chloride ion in the solution? (Kf for water is 1.86°C kg/mol).
what is the actual van't hoff factor for an aqueous 0.20 molal solution of FeCl3 if the freezing point is -1.2C? assume the Kf of water is 1.86C/m
For an aqueous solution of HF, determine the van't Hoff factor assuming 0% ionization. For the same solution, determine the van't Hoff factor assuming 100% ionization. A solution is made by dissolving 0.0300 mol HF in 1.00 kg of water. The solution was found to freeze at -0.0644°C. Calculate the value of i and estimate the percent ionization of HF in this solution.
[2.6] 6. a. Calculate the van't Hoff factor of a 0.085 M potassium sulfate solution that has an osmotic pressure of 5.4 atm at 25°C. b. Is this actual van't Hoff factor less than or greater than the ideal (expected) van't Hoff factor? Explain why the observed factor is different than the ideal factor.
lf a 0.880 m aqueous solution freezes at-3.50 °C, what is the van't Hoff factor, і, of the solute? Kt values can be found here. Number
Question 16 of 45 Submit FeCl3 has a van't Hoff factor of 3.4. What is the freezing point of an aqueous solution made with 1.71 m FeCl3? (Kf for water is 1.86 °C/m) °C 4 7 5 8 6 9 Question 20 of 45 Submit Determine AGº for the phase change CO2(g) → CO2(aq) at 25°C. AH° = -19.4 kJ/mol AS° = +92.3 J/mol-K kJ/mol (1 4 7 +/- 2 5 8 3 6 9 0 x 100 May 7...