The position vector of a particle of mass 2.10 kg as a function of time is given by r with arrow = (6.00 î + 5.80 t ĵ), where r with arrow is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time. k kg · m2/s
The position vector of a particle of mass 2.10 kg as a function of time is...
nts) The position vector of a particle of mass 2.5 kg as a function of time is given (6 7i+571), where is in meters and t is in seconds. Determine the angular momentum of the particle about the origin at t=2 seconds.
The vector position of a particle varies in time according to the expression r with arrow = 7.40 î − 5.00t2 ĵ where r with arrow is in meters and t is in seconds. (a) Find an expression for the velocity of the particle as a function of time. (Use any variable or symbol stated above as necessary.) v with arrow = m/s (b) Determine the acceleration of the particle as a function of time. (Use any variable or symbol...
The position vector of a particle whose mass is 3.0 kg is given by: r = 4 0i + 3.0t^2 j +10k, where r is in meters and t is in seconds. Determine the angular moment and the net torque about the origin acting on the particle. Two particles M_1 = 6.5 kg and M_2 = 3.1 kg are traveling with the velocities as shown below Determine the net angular momentum and use the right rule to determine its direction
Suppose that the position vector for a particle is given as a function of time by vector r (t) = x(t)î + y(t)ĵ, with x(t) = at + b and y(t) = ct2 + d, where a = 2.00 m/s, b = 1.50 m, c = 0.118 m/s2, and d = 1.02 m.
Suppose that the position vector for a particle is given as a function of time by (t) = x(t)î + y(t)ĵ, with x(t) = at + b and y(t) = ct2 + d, where a = 1.40 m/s, b = 1.50 m, c = 0.121 m/s2, and d = 1.18 m. (a) Calculate the average velocity during the time interval from t = 2.10 s to t = 3.90 s. = m/s (b) Determine the velocity at t = 2.10...
Suppose that the position vector for a particle is given as a function of time by vector r (t) = x(t)î + y(t)ĵ, with x(t) = at + b and y(t) = ct2 + d, where a = 2.00 m/s, b = 1.20 m, c = 0.121 m/s2, and d = 1.20 m. (a) Calculate the average velocity during the time interval from t = 2.05 s to t = 3.90 s. vector v = m/s (b) Determine the velocity...
A 1.30-kg particle moves in the xy plane with a velocity of = (4.10 î − 3.80 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is = (1.50 î + 2.20 ĵ) m.
The velocity of a particle of mass m = 2.10 kg is given by ý = -5.30 î + 3.009 m/s. What is the angular momentum of the particle around the origin when it is located at * = -9.00î – 4.30ſ m? L = kg: m m2/s
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i = 6.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 3.00...
A particle initially located at the origin has an acceleration of vector a = 4.00ĵ m/s2 and an initial velocity of vector v i = 9.00î m/s. (a) Find the vector position of the particle at any time t (where t is measured in seconds). ( t î + t2 ĵ) m (b) Find the velocity of the particle at any time t. ( î + t ĵ) m/s (c) Find the coordinates of the particle at t = 9.00...