A 1.30-kg particle moves in the xy plane with a velocity of = (4.10 î − 3.80 ĵ) m/s. Determine the angular momentum of the particle about the origin when its position vector is = (1.50 î + 2.20 ĵ) m.
A 1.30-kg particle moves in the xy plane with a velocity of = (4.10 î − 3.80 ĵ) m/s. Determine the angular momentum of...
A 1.80-kg particle moves in the xy plane with a velocity of V (4.10 1 - 3.10 j) m/s. Determine the angular momentum of the particle about the origin when its position vector is r = (1.50 + 2.20 j) m. i + j +
A 1.30-kg particle moves in the xy plane with a velocity of V - (3.90 i 3.20j) m/s. Determine the angular momentum of the particle about the origin when its position vector is r-(1.50i2.20 j) m. R)kg m2/s
A 1.96-kg particle has a velocity (2.08 î − 3.07 ĵ) m/s, and a 3.05-kg particle has a velocity (1.08 î + 5.96 ĵ) m/s. (a) Find the velocity of the center of mass. (b) Find the total momentum of the system.
At the instant of the figure, a 4.10 kg particle P has a position vector r of magnitude 9.10 m and angle θ1 = 44.0° and a velocity vector v of magnitude 4.60 m/s and angle θ2= 33.0°. Force F,of magnitude 5.30 N and angle θ3 = 33.0° acts on P. All three vectors lie in the xy plane. About the origin, what are the magnitude of (a) the angular momentum of the particle and (b) the torque acting on...
A 5.71 kg particle-like object moves in a plane with velocity components vx = 16.9 m/s and vy = 51.5 m/s as it passes through the point with (x, y) coordinates of (9.95, -7.85) m. Just then, in unit-vector notation, what is its angular momentum relative to (a) the origin and (b) the point (-6.87, -6.87) m?
The position vector of a particle of mass 2.10 kg as a function of time is given by r with arrow = (6.00 î + 5.80 t ĵ), where r with arrow is in meters and t is in seconds. Determine the angular momentum of the particle about the origin as a function of time. k kg · m2/s 6.00 і + 5.80 tj. where r ıs in meters and t is in seconds. Determine the angular momentum of the...
12. The angular position of the particle is (t)= 2 + 3t+ t(rad), its angular velocity at t = 3s is: * 5 (8 Points) none of them 22 1/s 16 1/s 25 1/5 9 1/3 13.A 2.50-kg particle moves in the xy plane with a velocity of v = 3 i +5k (m/s). Determine the angular momentum of the particle in Js, when its position vector is r = 7 i (m): * (7 points) 87,5j 21j none of...
A particle P with mass 5 kg has position vector r(r = 7.0 m) and velocity v(v = 5.0 m/s) as shown in the figure. It is acted on by force F(f = 8.0 N). All three vectors is in the xy plane. About the origin, what is the z-component of the angular momentum of the particle? About the origin, what is the z-component of the torque acting on the particle? About the origin, what is the z-component of the...
C. A 0-kg particle moves in the horizontal xy-plane motion under the action of a net forceEF(A+ 5?) N to a point A in the plane. The position vector from the origin to the point A is r-(-3i-210Dm i. What is the magnitude and direction of the linear momentum, Latt-5s The net moment I, acting on the particle at t-5 s
A particle whose mass is 2.0 kg moves in the xy plane with a constant speed of 3.0 m/s along the direction. What is its angular momentum (in kg/m 2 /s) relative to the point (0, 5.0) meters?