Homework Answers
Answer
-136 kJ
Explanation
2Mg(s) + O2(g) ------> 2MgO(s) ∆H°= -1203kJ
Stoichiometrically, ∆H° for two moles of Mg combustion is -1203 kJ
mole = mass/molar masd
moles of Mg = 5.49g/24.305g/mol = 0.2259mol
∆H° for combustion of 0.2259moles of Mg = (-1203kJ/2mol)×0.2259mol = -136 kJ
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