2. Hydrogen chloride adds ionically to alkenes. In each case, predict the course of the reaction of HCl with the following hydrocarbons by writing the structure of the product: (a) 1-butene, (b) 2- methylpropene, (c) 1-methyl-1-phenylethene.
3. Predict the course of the reaction of HBr with the substrates listed in Question 2 by providing the structure of the organic product. Assume that a free-radical process applies in all cases.
2. Hydrogen chloride adds ionically to alkenes. In each case, predict the course of the reaction...
Hydrogen chloride adds ionically to alkenes. In each case predict the major course of the reaction of HCL with the following hydrocarbons by writing the structure of the ORGANIC product: a) 1-butene, b) 2-methylpropene, c) 2-phenylpropene
also show the mechanism and curved arrows for each
mechanism
2. Predict the products for the reaction between le products for the reaction between Br, as well as Br/H, and the Alkenes listed below. rredict whether each reaction is syn- or anti-, Label the substrate, nucleophile and electrophile in each reaction. Substrate Structure Overall Reaction with Brz (with products) syn- or Overall Reaction with Bry/H20 (with products) anti- 3,3-dimethyl-1-1 butene 1-hexene styrene (phenylethene)
Predict the major organic product of the following reaction. When drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect Draw the structure of the alkene that reacts with HBr to give the following alkyl bromide as the major organic product Predict the product for the following reaction: When drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that...
Stereochemistry of Electrophilic Addition Reactions of Alkenes 4. Predict the product of the following reaction. Consider the stereochemistry of the product Br Br. cis-2-butene trans-2-butene + сна, CH2Cl2 5. Predict the product of the reaction. Is the product a terminal or internal alkyne? Br 1. Excess NaNH 2. H,O Br
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the elect HBr by the π electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the n electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1°<2°<3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior to the...
14,15,16,17,18
14. Provide the major organic product of the reaction below 2 CHIS 15. Draw the major organic product venerated in the reaction below. Pay particular attention to regio- and stereochemical detail. 1.0, 2. (CH 16. Addition of HCl to 3-methyl-1-butene yields a mixture of two constitutional alkyl chloride isomers. What are they likely to be and how are they formed? Give detailed equations. 17. If stereoisomers are considered, how many alkyl chlorides from #16, could be products? 18. Give...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior...
Electrophilic addition of HBr to alkenes yields a bromoalkane. The reaction begins with an attack on the hydrogen of the electrophilic HBr by the electrons of the double bond to give a carbocation. This step follows Markovnikov's rule with the electrophilic H atom adding to the sp2 carbon containing the most hydrogens, leading to the formation of the most stable carbocation (1° < 2° < 3°). If possible, a 1,2-shift of either a neighboring hydride or methyl group can occur prior...