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1. Find the stress distribution for the following structural member by calculating and plotting (to scale) the bending stress

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of neutral axis - from the - Hetermination bottom layer - - j A = 4 sq. in A₂ = 4 sq. in 4 q = 4.5 in = 2 in A + A2 1 => y =y = 51-3.25 3 . 2 - )کی کی 7- at top, Stress Stresia = کم) و هه مى ده جا 18- ib ba زين وا ط وا - 242 = ج 2 / ط 2 243 . 43 ك :neutralerisi متر - یه و bottom the from at t Stress . - 3025 هو هو - - 2 280 1262 ہ | خود طل83 - il883ت 2 مل گیا، l7L243- -Stress at the bottom - of = A x Y . 47 of = - 96000 x 3.25 78.1667 . Of . Oh = -17174.28 lo / sg. in = -2473096-38 lb/ft2- 25

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