minitab
Can anyone help me with minitab question?
The life spans of car batteries are normally distributed, with a mean of 44 months and a standard deviation of 5 months.
A car battery is selected at random. Find the probability that the life span of the battery is less than 36 months.
What is the shortest life expectancy a car battery can have and still be in the top 5% of life expectancies?
Ans:
Given that
mean=44
standard deviation=5
1)
z=(36-44)/5=-1.6
P(z<-1.6)=normsdist(-1.6)=0.0548
2)
P(Z>=z)=0.05
P(Z<=z)=1-0.05=0.95
z=normsinv(0.95)=1.645
shorted life expentancy to be in top 5%=44+1.645*5=52.225
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