Question 4 A manufacturer of car batteries claims that the life of his batteries is approximately...
Question 4
A manufacturer of car batteries claims that the life of his batteries is approximately normally distributed with a mean life of 7 years and a standard deviation equal to 2 year. What is the probability that a battery last between 1 and 13 years?
| a. |
p = 0.9974 |
|
| b. |
p =0.74 |
|
| c. |
p = 0.99 |
|
| d. |
p = -0.9974 |
Homework Answers
Ans. Let X be life of battery, and X has N( 7, 4)
p = P( 1 < X < 13)
= P[(1-7)/2 < (X-7)/2 < (13-7)/2]
= P (-3 < Z < 3)
= 2*P(0 < Z < 3), since Z is symmetrical distribution abuta z =0
=2*0.4987
=9974
Thus the correct answer is (a)
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Question 4
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