Question

Assume all temperatures to be exact. If 0.045 kg of ice at 0 ∘C is added to 0.330 kg of water at 41 ∘C in a 0.150-kg aluminum calorimeter cup, what is the final temperature of the water?

Answer 1

Here ,

mass of water , mw = 0.33 Kg

mass of ice , mi = 0.045 Kg

T1 = 0 degree C

T2 = 41 degree C

let the final temperature is Tf

heat lost by water + heat lost by aluminium = heat gain by ice

0.33 * 4186 * (41 - Tf) + 0.15 * 900 * (41 - Tf) = 0.045 * (334*1000 + 4186 * Tf)

solving for Tf

Tf = 27.65 degree C

the final temperature of the mixture is 27.65 degree C