Question

Why was 1mL of 3 M NaOH added to the aqueous solution of hexane-1,6-diamine in the synthesis of nylon (6,10)? Draw the structure you would expect for a nylon termed "Nylon (4,6)". A sample of the polymer polyethylene (PE) had an average molecular weight of 700,000, approximately how many ethylene (ethene) monomers were used to make it?

Answer 1

(3) NaOH was added to neutralise the HCl produced in the reaction.

NaOH was added to neutralise the HCl produced in the reaction. Sebacoyl Chloride (Decadioyl Chloride) (n may equal a few hundred to many thousand) + n HCl The structure of Nylon 4,6 is as shown. The molecular weight of ethylene is 28.05 g/mol. The molecular weight of polymer is 700,000 Number of ethylene monomers used = 700,000/28.05 = 24955

(4) The structure of Nylon 4,6 is as shown.

(5) The molecular weight of ethylene is 28.05 g/mol.
The molecular weight of polymer is 700,000
Number of ethylene monomers used $= \frac {700,000}{28.05} = 24955$