Solution:- Given that SE = 0.046, 99% confidence for Z = 2.576
(a) p = 0.5
n = (Z/SE)^2*p*q = (2.576/0.046)^2*0.5*0.5 = 784
(b) p = 0.13, q = 0.87
n = (2.576/0.046)^2*0.13*0.87 = 354.681 = 355.
R × R | x < y} . This means that R 10. Let R< = {(x, y) relation on R. is the "less than" 95 (a) What is the domain of the relation R<? (b) What is the range of the relation R<? (c) Is the relation R a function from R to R? Explai. Note: Remember that a relation is a set. Consequently, we can talk about one relation being a subset of another relation. Another thing to...
In the circuit shown, R₁ = 20 kΩ and R₂ = 10 kΩ.The voltage at terminal B can be varied from minimum (wiper moves towards resistor R₂) to maximum (wiper moves towards resistor R₁) by rotating the potentiometer shaft.
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solve for r 0/10 Correct C 2er; solve for r
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(20*10^-6)=(1.11*10^-10)/(1/r-1/2r) I need help in a step-by-step method that shows how to solve for r...