Question

Step 3 Next, find Q1. Recall that the first quartile, Q,, is the median of the lower half of the data. That is, the median of the data located below the Q2 position. Consider the ordered list of data values. The median, Q2, which was determined in the last step, has been underlined for clarity. 9, 12, 12, 13, 14, 14, 15, 16, 17 values to the left of the There are nine values in the whole data set, but there are only underlined median. The first quartile, Q, will be equal to the median of these values. Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values. sum of middle two values median 2 ahd The middle two values of the lower half of the data set are 12 Now, calculate the first quartile. Q1 12 + Q1 2 Skip (you cannot come back) Submit

Answer 1

Recall that the first quartile, Qy, is the median of the lower half of the data. That is, the median of the data located below the Q2 position. Consider the ordered list of data values. The median, Qy, which was determined in the last step, has been underlined for clarity. Median 9, 12, 12, 13, 14, 14, 15, 16, 17 There are nine values in the whole data set, but there are only 4 values to the left of the underlined median. The first quartile, Q, will be equal to the median of these values. Since the lower half of the data has an even number of data values, we will now use the rule to find the median of an even number of data values. sum of middle two values The middle two values of the lower half of the data set are 12 and 12 Now, calculate the first quartile. Q. 124 12 24 12

Substitute n = 1060 and f = 692 into the relative frequency formula and round your final answer to the nearest hundredth. relative frequency - 692 1060 0.65