3)
Given,
V1 = 1.5 V ; V2 = 1.2 V ; r1 = 0.5 Ohm ; r2 = 0.8 Ohm
2( i1 + i2) + 0.8 i2 = 1.2
2i1 + 2.8i2 = 1.2
2 (i1 + i2) + 0.5 i1 = 1.5
2.5 i1 + 2 i2 = 1.5
solving the above eqn we get
i1 = (1.5 - 2i2)/2.5
2/2.5 (1.5 - 2i2) + 2.8i2 = 1.2
i1 = 1.16 A and i2 = -0.4 A
So the current through 2 Ohm is:
I = 1.16 - 0.4 = 0.76 A
Hence, I = 0.76 A
b)No current will be delivered if we use only battery in the circuit
caos lock shit T Multiloop Circuits 2010 Make a sketch showing the junctions and loops for...