Question

HW#15 Determine the departures and latitudes, linear misclosure and relative precision for the traverse in HW#14 using the following measured horizontal distances around its sides. Side Horz. Distance AB 522.25 ft BC 565.87 ft CD 560.66 ft DE 452.11 ft EF 255.08 ft FA 640.52 ft

This is homework 14 answers, I need 15 answered

Answer 1

"Given Azimuth of AB = 145 degree 16' 24"" Azimuth of BC = 47 degree 6' 37.35"" Azimuth of CD = 355 degree 33' 20.66"" Azimuth of DE = 236 degree 38 degree 46.66"" Azimuth of EF = 226 degree 55' 14.9"" azimuth of FA = 130 degree 39'43.32"" We know that, Latitude = distance times cos(alpha) Departure = distance times sin(alpha) where, alpha is Azimuth or bearing rightarrow sum of latitudes or sum of departures of a closed transverse = 0. Linear misclosure = squareroot (-325.283)^2 + (590.515)^2 = 674.1787 ft. rightarrow Precision: -misclosure/transverse - perimeter = 674.1787/2996.49 = 0.224989 1/4.4446"
( Note: generally misclosure is not this much, check azimuth angles once again if they are correct, this answer also correct).