Question

An M-16 is fired from level ground at an upwards angle of 10 degrees with respect to the horizontal. The initial velocity of the bullet is 948 m/s, but because it is fired at a 10 degree angle, the vertical component of the initial velocity is 165 m/s and the horizontal component is 934 m/s. Ignore air resistance and the curvature of the earth in this problem. (Hint: See the videos Projectile Motion Parts 9-13. For questions 9-14 and 17, you do not need to do any calculations; these questions can be solved from information given in the problem and with concepts from the lecture videos.)

What is the initial horizontal velocity, v_xi, in m/s?   

An M-16 is fired from level ground at an upwards angle of 10 degrees with respect to the horizontal. The initial velocity of the bullet is 948 m/s, but because it is fired at a 10 degree angle, the vertical component of the initial velocity is 165 m/s and the horizontal component is 934 m/s. Ignore air resistance and the curvature of the earth in this problem. (Hint: See the videos Projectile Motion Parts 9-13. For questions 9-14 and 17, you do not need to do any calculations; these questions can be solved from information given in the problem and with concepts from the lecture videos.)

What is the initial vertical velocity, v_yi, in m/s?  (+ is for up, - is for down)

An M-16 is fired from level ground at an upwards angle of 10 degrees with respect to the horizontal. The initial velocity of the bullet is 948 m/s, but because it is fired at a 10 degree angle, the vertical component of the initial velocity is 165 m/s and the horizontal component is 934 m/s. Ignore air resistance and the curvature of the earth in this problem. (Hint: See the videos Projectile Motion Parts 9-13. For questions 9-14 and 17, you do not need to do any calculations; these questions can be solved from information given in the problem and with concepts from the lecture videos.)

What is the vertical acceleration, a_y, in m/s²? (+ is for up, - is for down)

An M-16 is fired from level ground at an upwards angle of 10 degrees with respect to the horizontal. The initial velocity of the bullet is 948 m/s, but because it is fired at a 10 degree angle, the vertical component of the initial velocity is 165 m/s and the horizontal component is 934 m/s. Ignore air resistance and the curvature of the earth in this problem. (Hint: See the videos Projectile Motion Parts 9-13. For questions 9-14 and 17, you do not need to do any calculations; these questions can be solved from information given in the problem and with concepts from the lecture videos.)

What is the final vertical velocity, v_xf, in m/s?

Answer 1

1) The initial horizontal velocity is given in the question, equal to 934 m/s.

2) The initial vertical velocity is given in the question, equal to 165 m/s.

3) Ignoring air, acceleration is only due to gravity (which acts downwards), thus,

$a_{y}=-9.8m/s^{2}$

4) Ignoring air, final velocity at the same level will be same as initial velocity (in magnitude). Thus,

Final vertical velocity is 165 m/s and final horizontal velocity is 934 m/s.