Question

Im getting the same output but I'm assuming I'm forgetting to incorporate the objective of evaluating in increments of 1 unit? How do I code that?

Instructions from your Teacher: run tests Write a program that prints to three significant figures the values of f(x) from x = 0 to x = 10 in increments of 1 unit. The values of x include 0 and 10. The function f(x) is defined below.. 1 import math 2 # funtion g(x) returns sqrt(x) when x<8 and returns 8<=X 3 def g(x): 4. if x<8: 5 # return sqrt(x) return math.sqrt(x) 7- else: 8 # return sqrt(8) 9 return math.sqrt(8) 10 11 # for x = 0 to x = 10 12 - for x in range (10): 13 print("%.3f' % g(x)) f(x) = ;x<8 ;8<x The output of the first and last values are below: 0.000 2.828 Python 3.8.1 (default, Feb 2 2020, 08:37:37) 0.000 1.000 1.414 1.732 2.000 2.236 2.449 2.646 2.828 2.828

Answer 1

f.py - D:/Coding/Python/f.py (3.7.4) File Edit Format Run Options Window Help import math def f(x): #If x<8, return sqrt (x) if x<8: return math.sqrt(x) #Return square root of 8 return 8**0.5 #Loop from 0 to 10 for x in range (11): #Print f(x) rounded to 3 decimal points print('%.3f'%f(x))

OUTPUT :

======================= RESTART: D: /Coding/Python/f.py - 0.000 1.000 1.414 1.732 2.000 2.236 2.449 2.646 2.828 2.828 2.828 >>> |

CODE :

import math
def f(x):
#If x<8, return sqrt(x)
if x<8:
return math.sqrt(x)
#Return square root of 8
return 8**0.5

#Loop from 0 to 10
for x in range(11):
#Print f(x) rounded to 3 decimal points
print('%.3f'%f(x))