Question

If 14.2 kg of A1,0,(s), 53.4 kg of NaOH(l), and 53.4 kg of HF(g) react completely, how many kilograms of cryolite will be produced? mass of cryolite produced: kg Na, AIF Which reactants will be in excess? NaOH A1,0 HF What is the total mass of the excess reactants left over after the reaction is complete? total mass of excess reactants: kg

Answer 1

Answer:

Answer: The formation of cryolite is girenky Al2O3 +6NaOH + H2H For 2 Naz Affo +9 HO. (82 q As 102 I mole Alals reacts with 6 miles of Mact & 12 molel tf & produces a moles of Cryolite. Now moles of the is taken a 14:2x103 1.39x10² moles Hfz 53.4x103 2.67x103 moles moles of NaOH = 53 4x 103 1:34 x 103 moles t3qxtoʻxt2 mesles of 462053 2*4-34X103 model of 27-47X 13 moter off mules of its 2 1.39x10² moles of the Iz reacts with 6X 1.39 X 10 & mules of Hot & 12X1.39x10² moles of HP. but mules of itf taken = 2.67X168 >1.67X10² moles of mules of Mwilt baken z 1-34X103 > 0.34x102 water of Hence Al2O3 is the writing reactant. & moles of Nas Affe produced = 1-39x102 x2 s moss of cryolite produced = 1.39x10²x210x2 58-38 kg Na3AlF6 Ans. HF reactants are present in excess Jus Malt I Nuolt 58.30

= Remaining mass NaOH = (13-4-834) X 10² moles 5.064102x40 20.24 kg & Remaining mass of HF = (26.7 - 1.67) X 102 moles = 25.03 X102 x 20 - 50.06 kg moss of reactants (excess) (inreacted) Hence total = 20.24f so-06 z7o.3 kg Ans