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11. A 20° full depth spur pinion is required to transmit 1.5 kW at a speed of 1230 rpm. If the pinion has 21 teeth and is man


Table 2. Useful range of gear ratios Gear Ratio Pitch Efficienc range line velocity Spur 1:1 to 6:1 25 m/s 98-99% Helical 1:1
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Answer #1

By using the lewis equation we can solve the problem design may be differ due to different consideration of value.

Solution- y = 0.154-0.912 for 20 full depth? Given Tp=21 Np - 12300pm P=1.5kW So y = 0.154 - 0.912 21 =0.4105 3+1.4m - 3 tue

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